no
when t=7, your denomintor is e^0 which is 1, the numberator is e^7, so you would have a value of
e^7/1 or e^7
consider k(t)=(e^t)/(e^t-7) on[-7,7]
Is this function continuous on the given interval? If it is continuous, type "continuous". If not, give the t -value where the function is not continuous.
The function is not continous and it is not continous on 7 (which is the t=value). Am I right?
2 answers
Is your denominator ((e^t)-7) or (e^(t-7))? The difference is important: if it's the first of these, the function would be discontinuous at t=ln(7). If it's the second, then it's not discontinuous over the range given.