The point (0,2) lies on the curve, so the tangent there is
y-2 = -2(x-0)
y" = -2y'
y' = -2, so y" > 0
so the graph is concave up
see what you can do with the last part.
consider dy/dx = 2-2y where y=f(x) is the particular solution to the differential equation where f(0)=2.
1. write an equation for the line tangent to f at x=0
2. is f concave up or down at (0,2)?
3. find f(x)
1 answer