Consider an asteroid with a radius of 15.5 km and a mass of 3.46E+15 kg. Assume the asteroid is roughly spherical. What is the acceleration due to gravity on the surface of the asteroid?

Question

Suppose the asteroid spins about an axis through its center, like the Earth, with a rotational period T. What is the smallest value $T$ can have before loose rocks on the asteroid's equator begin to fly off the surface?

Answer 1

Fg=GM/radius^2

centripetal acceleration=w^r r

where w=2PI/PeriodT