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Consider a spinner with numbers 1-8 and a number cube with numbers 1-6. Let event A represent landing on a number greater than...Question
Consider a spinner with numbers 1–8 and a number cube with numbers 1–6. Let event A represent landing on a number greater than 3 on the spinner and event B represent rolling a number greater than 3 on the number cube. Find P(A∩B) . Enter your response as a fraction.(1 point)
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GPT-4o mini
To find \( P(A \cap B) \), we first need to determine the probabilities of each individual event \( A \) and \( B \).
1. **Event A**: Landing on a number greater than 3 on the spinner.
- The numbers on the spinner are 1, 2, 3, 4, 5, 6, 7, 8.
- The numbers greater than 3 are: 4, 5, 6, 7, 8.
- There are 5 favorable outcomes (4, 5, 6, 7, 8) out of 8 possible outcomes.
- Therefore,
\[
P(A) = \frac{5}{8}
\]
2. **Event B**: Rolling a number greater than 3 on the number cube.
- The numbers on the number cube are 1, 2, 3, 4, 5, 6.
- The numbers greater than 3 are: 4, 5, 6.
- There are 3 favorable outcomes (4, 5, 6) out of 6 possible outcomes.
- Therefore,
\[
P(B) = \frac{3}{6} = \frac{1}{2}
\]
3. **Finding \( P(A \cap B) \)**:
- Assuming the spinner and cube are independent, we can find the joint probability \( P(A \cap B) \) by multiplying the probabilities of \( A \) and \( B \):
\[
P(A \cap B) = P(A) \times P(B) = \frac{5}{8} \times \frac{1}{2}
\]
\[
= \frac{5 \times 1}{8 \times 2} = \frac{5}{16}
\]
Thus, the probability \( P(A \cap B) \) is
\[
\boxed{\frac{5}{16}}
\]
1. **Event A**: Landing on a number greater than 3 on the spinner.
- The numbers on the spinner are 1, 2, 3, 4, 5, 6, 7, 8.
- The numbers greater than 3 are: 4, 5, 6, 7, 8.
- There are 5 favorable outcomes (4, 5, 6, 7, 8) out of 8 possible outcomes.
- Therefore,
\[
P(A) = \frac{5}{8}
\]
2. **Event B**: Rolling a number greater than 3 on the number cube.
- The numbers on the number cube are 1, 2, 3, 4, 5, 6.
- The numbers greater than 3 are: 4, 5, 6.
- There are 3 favorable outcomes (4, 5, 6) out of 6 possible outcomes.
- Therefore,
\[
P(B) = \frac{3}{6} = \frac{1}{2}
\]
3. **Finding \( P(A \cap B) \)**:
- Assuming the spinner and cube are independent, we can find the joint probability \( P(A \cap B) \) by multiplying the probabilities of \( A \) and \( B \):
\[
P(A \cap B) = P(A) \times P(B) = \frac{5}{8} \times \frac{1}{2}
\]
\[
= \frac{5 \times 1}{8 \times 2} = \frac{5}{16}
\]
Thus, the probability \( P(A \cap B) \) is
\[
\boxed{\frac{5}{16}}
\]
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