consider a series R-C circuit consisting of a 30 ohm resistor and 20*10^-6F capacitor connected to a 100V,50Hz power supply.find the magnitude of the current and the angle by which the current leads the voltage.

Answer 1

Xc = 1/WC = -1/(314.2*20*10^-6) = -159.2 Ohms.

Z(Ohms) = 30 -j159.2 = 162[-79.3o].

I = E/Z = 100[0o]/162[-79.3] = 0.617A[79.3o].