p: percentage (4.5% is burned in 155s)
m:mass of rocket
u:fuelspeed in meter/s!
v=u*ln(1/(1-p))=1500*ln(1/0.955)
a=v/t
Consider a rocket in space that ejects burned fuel at a speed of 1.5 km/s with respect to the rocket. The rocket burns 9 % of its mass in 310 s (assume the burn rate is constant).
(a) What is the speed of the rocket after a burn time of 155.0 s? (suppose that the rocket starts at rest; and enter your answer in m/s)
unanswered
(b) What is the instantaneous acceleration of the rocket at time 155.0 s after the start of the engines?(in m/s )
4 answers
Its incorrect
no it is correct
in numbers 256.5 and 1.71 respectively?