Consider a normal population with μ = 36 and σ = 4.9. Calculate the z-score for an x of 47.6 from a sample of size 14. (Give your answer correct to two decimal places.)
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Z = (score-mean)/SD
If you know the mean and SD for the population, sample size is extraneous information for determining the Z score for an individual raw score.
If you know the mean and SD for the population, sample size is extraneous information for determining the Z score for an individual raw score.
Could this z-score be used in calculating probabilities using Table 3 in Appendix B? Why or why not?