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Consider a hoola-hoop of radius R and it is spinning about its symmetry axis at a constant angular velocity. Now, I double its...Asked by lacey
Consider a hoola-hoop of radius R and it is spinning about its symmetry axis at a constant angular velocity. Now, I double its mass and halve its angular velocity. What is the new angular momentum in terms of the initial angular momentum?
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Answered by
Damon
L = I w = m R^2 w
L2 = 2 m R^2 w/2
which is the same
L2 = 2 m R^2 w/2
which is the same
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