well, for v = 10 for example
F = .5 (.38)(1.77)(1.2)(100)
for v = 15 then
F = F at 10 (225/100)
and for v = 20
F = F at 10 (400/100)
etc
graphs
F vs v is parabola
F vs v^2 is straight line
Consider a carwith front cross-sectional area of A=(1.77 ± 0.02)m^2 and a drag coefficient of C=(0.38±-0.02) moving with a speed of v=(10.0±0.5)m/s. Suppose that the density of air is p=1.20 kg/m^3 at the sea level.
1.Calculate the force F=(1/2)CApv^2 on the car due to air friction.
2.Find the forces due to air friction on the car for the following speeds
(a)(10.0±0.5)m/s
(b)(15.0±0.5)m/s
(c)(20.2±0.6)m/s
(d)(25.5±0.7)m/s
(e)(30.3±0.7)m/s
3.Produce two graphs of (i)F vs. v and
(ii)F vs. v^2.
1 answer
1 answer