I will assume that in each case, the first ball drawn is not returned.
prob(2 blue) = (12/35)(11/34) = ..
prob(2 yellow) = you do it
prob(red, then yellow) = (14/35)(9/34) = ...
prob(red, then yellow) = your turn again
Consider a box that contains 14 red balls,12 blue balls and 9 yellow balls.A ball is drawn at random and the color is noted and then put back inside the box.Then,another ball is drawn at random.Find the probability?
a.both are blue
b.both balls are yellow
c.the first is red and the second is yellow
d.the first is red and the second is blue
3 answers
fr esg
Consider a box that contains 14 red balls, 12 blue balls, and 9 yellow balls.