Consider a bowl containing 36 different slips of paper. Ten of the slips of paper each contain one of 16)

the digits from the set 0 through 9 and 26 slips each contain one of the 26 letters of the alphabet. If
one slip is drawn at random, what is P(odd number or a consonant)?

21 consonants and 5 odd numbers. Would my answer be 21/36 + 5/36= 26/36

I am given a choice for answers: A)0, B) 21/36, C) 5/36 D) 26/36

1 answer

correct