Try the binomial probability function:
P(x) = (nCx)(p^x)[q^(n-x)]
x = 10
n = 20
p = 0.45
q = 1 - p = 1 - 0.45 = 0.55
Substitute the values and calculate.
An easier way would be to use a binomial probability table with the values stated above.
I hope this will help.
Consider a binomial experiment with 20 trials and probability 0.45 on a single trial. Use the normal distribution to find the probability of exactly 10 successes. Round your answer to the thousandths place.
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