To solve this problem, we can use the conservation of energy principle, which states that the total energy of a system remains constant.
Initially, the object has a kinetic energy of 220 J. As it moves upward, the kinetic energy is converted into potential energy. At its highest point, when it momentarily stops, all of its kinetic energy is converted into potential energy.
The potential energy (PE) of an object at a height (h) is given by the equation:
PE = mgh
Where m is the mass of the object (2 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height.
To calculate the height (h), we can rearrange the equation to solve for h:
h = PE / (mg)
Plugging in the values, we get:
h = 220 J / (2 kg * 9.8 m/s^2)
h = 22.45 m
Therefore, the object travels approximately 22.45 meters high.
CONSERVATION OF ENERGY
A 2kg object is tossed upward with a kinetic energy of 220 J. How high does the object travel?
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