Question

consecutive odd integer problem
find two odd integers the sum of whose squares is 130.
(sq)=squared

let x= 1st odd int
let x+2=2nd odd int

(2x+2)(2x+2)=130
4x(sq) + 4x+ 4x +4=130
4x(sq) + 8x -126= 0

2(2x(sq)+4x-63)=0
My question:
the two numbers to factor the equation.
pair of #s that multiplies to -126
and the same pair that adds to a 4.

Answer 1

found it set it up wrong was the problem :)