Congruency of Triangles Quick Check 4 of 54 of 5 Items Question Use the image to answer the question. To prove the triangles are congruent, which of the following rigid motions would map △PBK to △LQA ? (1 point) Responses translation along the vector so that point B maps to point A translation along the vector so that point upper B maps to point upper A rotation of 180° (counterclockwise) about point B rotation of 180 degrees (counterclockwise) about point upper B translation along the vector so that point B maps to point Q translation along the vector so that point upper B maps to point upper Q translation along the vector so that point P maps to point A translation along the vector so that point upper P maps to point upper A Skip to navigation page 9 of 9 Formula keypad has been closed. Press Control + Backslash to open it again.Formula keypad has been closed. Press Control + Backslash to open it again.Formula keypad has been closed. Press Control + Backslash to open it again.Formula keypad has been closed. Press Control + Backslash to open it again.Formula keypad has been closed. Press Control + Backslash to open it again.

1 answer

To determine which rigid motion would map triangle \( \triangle PBK \) to triangle \( \triangle LQA \), we need to analyze the correspondence between the vertices of the triangles and the transformations applied.

We assume the following correspondences based on the labels:

  • \( P \rightleftharpoons L \)
  • \( B \rightleftharpoons Q \)
  • \( K \rightleftharpoons A \)

To map \( \triangle PBK \) to \( \triangle LQA \), we should consider how each vertex from triangle \( PBK \) maps to the respective vertex in triangle \( LQA \).

Given the options for rigid motions, we need to find a transformation that maintains the structure of the triangles and correctly maps each vertex accordingly.

  1. Translation along the vector so that point B maps to point A - This would not work since it wouldn't correspond to the other points correctly.
  2. Translation along the vector so that point B maps to point Q - Again, this wouldn't work for the other points.
  3. Rotation of 180° (counterclockwise) about point B - This may or may not work, depending on the positions of \( A, Q, L, \) and \( P \).
  4. Rotation of 180° (counterclockwise) about point P - This transformation would also require further analysis regarding the positions of points \( Q, L, K, \) and \( A \).
  5. Translation along the vector so that point P maps to point A - This initially seems plausible until we check the other points.
  6. Translation along the vector so that point P maps to point A - Again, requires checking.

Without specific coordinates or visual information of the triangles, the best approach is identifying how these transformations would position each point relative to each other.

Typically, if two triangles can be shown to overlap perfectly via a translation or rotation, that motion would prove congruence.

Given none of the options can be decisively concluded without seeing the image:

From common transformations:

  • If the images of the vertices indicate a clear rotational symmetry, selecting the appropriate rotation about a key vertex (likely B or P) might be the right option.

Based on this information, if you were to carefully assess mappings, you would look for a rigid motion that allows all vertices of triangle \( PBK \) to coincide with their counterparts in triangle \( LQA \).

Final Recommendation: If the analysis of which point aligns best suggests that one vertex needs to undergo a systematic rotation mapping all sides across to their corresponding pairs, this motion would be most appropriate.

In a test scenario, carefully choosing "rotation of 180° (counterclockwise) about point B" or any translation making sure all points correspond at once would be ideal.

Make your selection based on verifying images of the triangles if available; the most likely correct answer here under common scenarios would involve a significant motion such as a key rotation or effective translation aligning \( PB, BK, \) and \( KQ \) to \( A, Q, L \).

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