To find the measure of angle \( \angle P \) in triangle \( \Delta OPQ \), we can use the property that the sum of the angles in a triangle is always 180 degrees.
We know:
- \( \angle T = 44^\circ \)
- \( \angle R = 26^\circ \)
First, we can find the measure of angle \( \angle S \) in triangle \( \Delta RST \):
\[ \angle S = 180^\circ - (\angle R + \angle T) = 180^\circ - (26^\circ + 44^\circ) = 180^\circ - 70^\circ = 110^\circ \]
Since the triangles are congruent (\( \Delta OPQ \cong \Delta RST \)), the corresponding angles are also congruent. Thus, we have:
\[ \angle P = \angle S = 110^\circ \]
Therefore, the measure of \( \angle P \) is \( 110^\circ \).