Confused, conflicting texts
when you are finding % error for density
formula: experienced value-accepted value/ accepted value ×100. Does the ×100 cancel out the percent sign?
EX; 7.28g/mL-6.54g/mL/6.54g/mL ×100. Is the answer 11.31 or 11.31%
The lab video did not multiply the 100, but everything else I see says11.31g/mL%
Thank you, lulu
2 answers
a) How will increasing the concentration of CO shift the equilibrium?
Suppose we have 5 apples and 5 oranges. The FRACTION of apples is 5/10 = 0.5. To change to percent, it's the fraction x 100 so 0.5 x 100 = 50%. The 100 ADDS the percent sign.
% = [(exp-accepted)/acceted]*100. If you want to remove the 100, then the % answer changes to the fraction. The answer in your question is 11.31%.
% = [(exp-accepted)/acceted]*100. If you want to remove the 100, then the % answer changes to the fraction. The answer in your question is 11.31%.
3 answers