To calculate the volume of a cone, we use the formula:
\[ V = \frac{1}{3} \pi r^2 h \]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height of the cone, and
- \( \pi \) is approximately 3.14.
Given:
- \( r = 4 \) feet,
- \( h = 12 \) feet,
- \( \pi = 3.14 \).
Now we can plug in the values:
\[ V = \frac{1}{3} \times 3.14 \times (4^2) \times 12 \]
Calculating \( 4^2 \):
\[ 4^2 = 16 \]
Now, substitute that into the formula:
\[ V = \frac{1}{3} \times 3.14 \times 16 \times 12 \]
Now calculate \( 16 \times 12 \):
\[ 16 \times 12 = 192 \]
Now, substitute that back into the equation:
\[ V = \frac{1}{3} \times 3.14 \times 192 \]
Now, calculate \( 3.14 \times 192 \):
\[ 3.14 \times 192 = 602.88 \]
Now calculate \( \frac{1}{3} \times 602.88 \):
\[ V = 200.96 \]
Thus, the volume of the cone-shaped container is approximately:
\[ \boxed{200.96} \text{ cubic feet} \]