Let's assume that the initial volume of syrup is V and the initial weight of syrup is W.
We know that the concentration of the syrup is 24%, so the weight of sugar in the initial syrup is:
0.24W
We want to obtain 100 kg of syrup containing 64% sugar, so the weight of sugar in the final syrup is:
0.64 x 100 kg = 64 kg
Let's assume that we need to evaporate x kg of water to obtain the final syrup.
The weight of sugar in the evaporated water is:
0.24x
The weight of sugar in the remaining syrup is:
0.24W - 0.24x
We want the weight of sugar in the final syrup to be 64 kg, so we can write the following equation:
0.24W - 0.24x = 64
We know that the initial concentration of the syrup is 24%, so we can write:
W = V x 0.24
If we assume that the density of the syrup is 1 kg/L, then:
W/V = 1 kg/L
W = V
Substituting W in the first equation, we get:
0.24V - 0.24x = 64
Dividing by 0.24, we get:
V - x = 266.67
We want to obtain 100 kg of syrup, so:
V - x = 100
Substituting V - x in the previous equation, we get:
V - x = 266.67
x = 166.67 kg
Therefore, we need to evaporate 166.67 kg of water to obtain 100 kg of syrup containing 64% sugar.
Concentration of syrup containing 24% sugar by weight by evaporation How much water should be evaporated for 100 kg of syrup containing 64% sugar to be obtained
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