compute the inverse laplace transform 2S^2+13S+5/(s+3)(s-1)^2

Question

i got 3e^t+5e^t+3e^t, not sure it correct

Answer 1

Hmm. I get

-3te^-t + 6e^-t - 4e^-3t

since (2s^2+13s+5) / ((s+3)(s+1)^2) = -3/(s+1)^2 + 6/(s+1) - 4/(s+3)