Compute algebraically the resultant Of following coplanar force : 100N at 30° , 141.4N at 45° and 100N at 240°
3 answers
100cis30° + 141.4cis45° + 100cis240° = 136.6 + 63.38i = 150.6 @ 24.9°
sdfsd
F= f1 +f2
F1=100cos30 + 141.4cos45 + 100cos240
=136.6i
F2=100sin30 + 141.4sin45 + 100sin240
=63.4j
R^2 =f^2 +f^2
R= 0.15kN at 25
Tan= y/x
F1=100cos30 + 141.4cos45 + 100cos240
=136.6i
F2=100sin30 + 141.4sin45 + 100sin240
=63.4j
R^2 =f^2 +f^2
R= 0.15kN at 25
Tan= y/x
2 answers