Compute A710_{16} + 51_{16} + B8AE_{16} in base 16.

Answer 1

To compute A710_{16} + 51_{16} + B8AE_{16} in base 16, we first need to convert each hexadecimal number to decimal:

A710_{16} = 10*16^3 + 7*16^2 + 1*16^1 + 0*16^0 = 42768_{10}
51_{16} = 5*16^1 + 1*16^0 = 81_{10}
B8AE_{16} = 11*16^3 + 8*16^2 + 10*16^1 + 14*16^0 = 47150_{10}

Now, we add the decimal numbers together:

42768_{10} + 81_{10} + 47150_{10} = 89999_{10}

Finally, we convert the sum back to hexadecimal:

89999_{10} = 15*16^3 + 13*16^2 + 15*16^1 + 14*16^0 = FDFE_{16}

Therefore, A710_{16} + 51_{16} + B8AE_{16} = FDFE_{16} in base 16.