work input=force*distance=3*.6 Joules
PE at top: mgh
mgh=1.8J
solve for height h.
Compressed air is used to fire a 50g ball vertically upward from a 0.60-m-tall tube. The air exerts an upward force of 3.0N on the ball as long as it is in the tube.
How high does the ball go above the top of the tube?
3 answers
some PE is gainied from work going up the tube, so h above yields the height it went above the bottom of the tube, so how high above the top of the tube, subract .6m
6.89m