There is no solution to #1 since 12 is not less than 0.
As written
12 < 12 + 4x < 0
means 12 < 12+4x AND 12+4x < 0
To find such a number, you would need
12 < 0
12 – x > 15 or 7x – 13 > 1
12-x > 15
-3 > x
7x-13 > 1
7x > 14
x > 2
You are correct
Compound Inequalities
Definition Words
◦Compound inequalities
◦And
◦Or
◦Intersection
◦Union
1). 12 < 12 + 4x < 0
2). 12 – x > 15 or 7x – 13 > 1
I divide it up the compound inequalities into two problems
12 <12+ 4x
4 x >0
or
x >0
and
12+4x <0
4 x < -12
x < - 3
so x is either left of -3 or right of 0 on a number line
12 - x > 15
-x > 3
I then multiplied both sides by -1 and changed the direction of the arrow when I changed the signs.
x < - 3
7 x - 13 > 1
7 x > 14
x > 2
so x is left of -3 or right of +2
I need someone to check and see if this is correct and how do I use the vocabulary words correctly. I'm having a difficult time with this.
1 answer