To determine the area of the circular layer of oil after \( t \) hours, we need to compose the two functions given:
- The area of a circle, given by \( A(r) = \pi r^2 \).
- The radius function, given by \( r(t) = 0.5t^3 \).
The composition of the functions is given by \( (A \circ r)(t) = A(r(t)) \).
First, substitute \( r(t) \) into the area function:
\[ A(r(t)) = A(0.5t^3) = \pi (0.5t^3)^2 \]
Calculating this, we have:
\[ (0.5t^3)^2 = 0.25t^6 \]
Thus, the area function becomes:
\[ A(r(t)) = \pi \cdot 0.25t^6 = 0.25\pi t^6 \]
So the composite function is:
\[ (A \circ r)(t) = 0.25\pi t^6 \]
Now, for the domain of this function, since \( t \) represents time and cannot be negative, the domain is \( t \geq 0 \).
Therefore, the correct response is:
\[ (A \circ r)(t)=0.25\pi t^6 \text{ and the domain is } t \geq 0. \]