I=V/Z=(1+j)/(2-j)
multipy num and denom by 2+j
(1+j)(2+j)/3=(2+j+2j-1)/3=(1+3j)/3
Complex numbers are often used when dealing with alternating current (AC) circuits. In the equation V = IZ, V is voltage, I is current, and Z is a value known as impedance. If V = 1+i and Z=2-$, find I.
2 answers
I=1/5+3/5i