Completely factor the expression by grouping, if possible.

Question

p2−pt−6p+6t

Answer 1

To factor the expression by grouping, we can rearrange the terms as:

p^2 - pt - 6p + 6t

Now, let's group the terms:

(p^2 - pt) - (6p - 6t)

Now, let's factor out the common terms from each group:

p(p - t) - 6(p - t)

Notice that both terms have a common factor of (p - t). We can now factor out this common factor:

(p - t)(p - 6)

Therefore, the completely factored expression is (p - t)(p - 6).