Complete the tables to show that y=kf(x)

results in the parent function being vertically compressed when k=1/2
.(1 point)
x y=x4
0 0
1 1
2 16
x y=1/2x4
0 0
1
2

1 answer

To demonstrate that the function \( y = \frac{1}{2}f(x) \) results in a vertical compression of the parent function \( y = f(x) = x^4 \) when \( k = \frac{1}{2} \), we will complete the second table (for \( y = \frac{1}{2}x^4 \)) based on the values from the first table.

Parent Function Table (y = x^4)

| x | y = x^4 | |-----|-----------| | 0 | 0 | | 1 | 1 | | 2 | 16 |

Compressed Function Table (y = 1/2 x^4)

To calculate the values for the second table, we will take the values from the first table and multiply them by \(\frac{1}{2}\):

  • For \( x = 0 \): \( y = \frac{1}{2} \cdot 0^4 = \frac{1}{2} \cdot 0 = 0 \)
  • For \( x = 1 \): \( y = \frac{1}{2} \cdot 1^4 = \frac{1}{2} \cdot 1 = \frac{1}{2} \)
  • For \( x = 2 \): \( y = \frac{1}{2} \cdot 2^4 = \frac{1}{2} \cdot 16 = 8 \)

Complete Compressed Function Table (y = 1/2 x^4)

| x | y = 1/2 x^4 | |-----|---------------| | 0 | 0 | | 1 | 0.5 | | 2 | 8 |

Summary:

  • At \( x=0 \), \( y=0 \) remains the same.
  • At \( x=1 \), \( y=1 \) is vertically compressed to \( y=0.5 \).
  • At \( x=2 \), \( y=16 \) is vertically compressed to \( y=8 \).

This confirms that the function \( y = \frac{1}{2}x^4 \) is a vertically compressed version of the parent function \( y = x^4 \).

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