Complete the table to vertically stretch the parent function f of x equals X cubed by a factor of 3 0 1 2

1 answer

To vertically stretch the parent function \( f(x) = x^3 \) by a factor of 3, we modify the function as follows:

\[ g(x) = 3 \cdot f(x) = 3x^3 \]

Now, let's compute the values for different inputs (0, 1, and 2) for both the parent function \( f(x) \) and the vertically stretched function \( g(x) \).

Table

| \( x \) | \( f(x) = x^3 \) | \( g(x) = 3x^3 \) | |---------|------------------|---------------------| | 0 | 0 | 0 | | 1 | 1 | 3 | | 2 | 8 | 24 |

Explanation:

  • For \( x = 0 \):

    • \( f(0) = 0^3 = 0 \)
    • \( g(0) = 3 \cdot 0^3 = 0 \)
  • For \( x = 1 \):

    • \( f(1) = 1^3 = 1 \)
    • \( g(1) = 3 \cdot 1^3 = 3 \)
  • For \( x = 2 \):

    • \( f(2) = 2^3 = 8 \)
    • \( g(2) = 3 \cdot 2^3 = 24 \)

This gives you the completed table for the parent function and the vertically stretched function.