Question

Complete the table to practice finding starting values in equations.

The starting value in y=mx+b is the variable

*blank 1*

"y is 40 more than 5 times x"

"y is 3 more than twice the value of x"

y is 10 more than 6 multiplied by x

Equation: y = 5x + 40

Equation: y = 2x + 3

Equation: *blank 2*

b = 40

b = *blank 3*

b = *blank 4*



Options for blank 1

A m
B x
C b
D y

Options for blank 2

A y = (6 + 10) * x

B y = 10x + 6

C y = 6x + 10

Options for blank 3

A 2
B y
C x
D 3

Options Blank 4

A y
B 6
C 10
D x

Answer 1

Let's complete the table based on the given equations and descriptions.

1. For *blank 1*, we need to identify the variable in the equation format \( y = mx + b \). The starting value in this context is represented by \( b \) (the y-intercept); therefore, the answer is:

**C b**

2. For *blank 2*, we need to express "y is 10 more than 6 multiplied by x" in the slope-intercept form. This can be written as:

**C y = 6x + 10**

3. For *blank 3*, we need to find the y-intercept \( b \) for the equation from *blank 2* \( y = 6x + 10 \), which clearly shows \( b = 10 \):

**C 10**

4. For *blank 4*, since we are looking for the y-intercept \( b \) in the equation \( y = 6x + 10 \), it is again \( 10 \). Therefore, we would have:

**C 10**

So the completed table looks like this:

- *blank 1*: C b
- *blank 2*: C y = 6x + 10
- *blank 3*: C 10
- *blank 4*: C 10