Question

Complete the table for the given function. Show your work.

x y = x2 + (-3)
0
1
2
3

A. -3, -2, 1, 6

B. 3, 4, 7, 12,

C. 0, 1, 4, 9,

D. none of the above.

Answer 1

To evaluate the function for each value of x, we need to substitute x into the given equation and simplify:

When x = 0: y = 02 + (-3) = 0 + (-3) = -3
When x = 1: y = 12 + (-3) = 1 + (-3) = -2
When x = 2: y = 22 + (-3) = 4 + (-3) = 1
When x = 3: y = 32 + (-3) = 9 + (-3) = 6

So the completed table of values is:

x | y
--|--
0 | -3
1 | -2
2 | 1
3 | 6

Therefore, the answer is (A) -3, -2, 1, 6.

Answer 2

For the function y = x^2 + (-3), we need to find the corresponding y values for each x value.

For x = 0:
y = (0)^2 + (-3) = 0 + (-3) = -3

For x = 1:
y = (1)^2 + (-3) = 1 + (-3) = -2

For x = 2:
y = (2)^2 + (-3) = 4 + (-3) = 1

For x = 3:
y = (3)^2 + (-3) = 9 + (-3) = 6

So, the table is:

x | y
--+---
0 | -3
1 | -2
2 | 1
3 | 6

Thus, the answer is (A) -3, -2, 1, 6.