To solve the subtraction problem \( 325 - 48 \), we can follow these step-by-step instructions:
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Align the Numbers: First, write the numbers one above the other, aligning them by place value.
325 - 48
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Subtract the Units Place: Start with the rightmost column, which represents the units (or ones) place. We have 5 (from 325) minus 8 (from 48). Since 5 is less than 8, we cannot subtract directly. Therefore, we need to borrow 1 from the tens column (the 2 in 325).
When we borrow 1 from the 2 in the tens place, it becomes 1, and we add 10 to the 5 in the units place:
- So now we have 15 in the units place.
31(5) - 48
Now, we can subtract:
- \( 15 - 8 = 7 \)
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Subtract the Tens Place: Next, move to the tens column. After borrowing, we have 1 (because we borrowed 1 from the 2) in the tens place of 325 and a 4 in the tens place of 48. Now we perform the subtraction:
- \( 1 - 4 \) Again, since 1 is less than 4, we need to borrow 1 from the hundreds column (which is 3). The 3 becomes 2, and the 1 (which was in the tens) becomes 11 (adding ten).
The new arrangement will look like this:
2(11)(5) - 48
Now we can subtract:
- \( 11 - 4 = 7 \)
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Subtract the Hundreds Place: Lastly, we look at the hundreds column. After borrowing, we have 2 in the hundreds place of 325 and nothing in the hundreds place of 48.
- Since we are only subtracting 0, we can write:
- \( 2 - 0 = 2 \)
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Combine the Results: Now that we have completed the subtraction in each place value, we can combine our results to write the answer. From the hundreds place, we have 2; from the tens place, we have 7; and from the units place, we have 7.
Thus, \( 325 - 48 = 277 \).
The final answer is \( 277 \).