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Complete the statement with an equation that makes the statement true.(1 point) The system of equations 3x+4y=1 and y= has an i...Asked by x
Complete the statement with an equation that makes the statement true.(1 point)
The system of equations 3x+4y=1
and y= ( )
has an infinite number of solutions.
The system of equations 3x+4y=1
and y= ( )
has an infinite number of solutions.
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Answered by
GPT-4o mini
For the system of equations to have an infinite number of solutions, the second equation must be a multiple of the first equation.
Starting with the equation \( 3x + 4y = 1 \), we can solve for \( y \):
1. Rewrite the original equation:
\( 4y = 1 - 3x \)
2. Divide everything by 4:
\( y = \frac{1}{4} - \frac{3}{4}x \)
Now, say we multiply the entire equation by any non-zero constant \( k \).
For example, let \( k = 2 \):
\[
y = 2 \left(\frac{1}{4} - \frac{3}{4}x\right) = \frac{1}{2} - \frac{3}{2}x
\]
The equation that results is:
\[
y = -\frac{3}{2}x + \frac{1}{2}
\]
Thus, completing the statement:
The system of equations 3x + 4y = 1 and \( y = -\frac{3}{2}x + \frac{1}{2} \) has an infinite number of solutions.
You could also choose other multiples, but they all must reflect the linear relationship derived from the original equation.
Starting with the equation \( 3x + 4y = 1 \), we can solve for \( y \):
1. Rewrite the original equation:
\( 4y = 1 - 3x \)
2. Divide everything by 4:
\( y = \frac{1}{4} - \frac{3}{4}x \)
Now, say we multiply the entire equation by any non-zero constant \( k \).
For example, let \( k = 2 \):
\[
y = 2 \left(\frac{1}{4} - \frac{3}{4}x\right) = \frac{1}{2} - \frac{3}{2}x
\]
The equation that results is:
\[
y = -\frac{3}{2}x + \frac{1}{2}
\]
Thus, completing the statement:
The system of equations 3x + 4y = 1 and \( y = -\frac{3}{2}x + \frac{1}{2} \) has an infinite number of solutions.
You could also choose other multiples, but they all must reflect the linear relationship derived from the original equation.
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