complete the square

Question

X2-4x+y2+6y=0

Show work please

Answer 1

divide the 1st order terms' coefficients by 2, and square the results

x^2 - 4 x + (-4/2)^2 + y^2 + 6 y + (6/2)^2 = (-2)^2 + 3^2

(x - 2)^2 + (y + 3)^2 = 13