To complete the square for the equation \( x^2 + 12x - 14 = 0 \), follow these steps:
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Start with the equation: \[ x^2 + 12x - 14 = 0 \]
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Move the constant term to the other side of the equation: \[ x^2 + 12x = 14 \]
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To complete the square, take half of the coefficient of \( x \) (which is 12), square it, and add it to both sides. Half of 12 is 6, and squaring it gives: \[ 6^2 = 36 \]
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Add 36 to both sides: \[ x^2 + 12x + 36 = 14 + 36 \]
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Simplify the right side: \[ x^2 + 12x + 36 = 50 \]
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Now, the left side can be written as a square: \[ (x + 6)^2 = 50 \]
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Finally, take the square root of both sides: \[ x + 6 = \pm \sqrt{50} \]
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Simplifying \(\sqrt{50}\): \[ \sqrt{50} = 5\sqrt{2} \]
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Thus, we have: \[ x + 6 = 5\sqrt{2} \quad \text{or} \quad x + 6 = -5\sqrt{2} \]
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Solving for \( x \): \[ x = -6 + 5\sqrt{2} \quad \text{or} \quad x = -6 - 5\sqrt{2} \]
So the solutions to the equation \( x^2 + 12x - 14 = 0 \) are: \[ x = -6 + 5\sqrt{2} \quad \text{and} \quad x = -6 - 5\sqrt{2} \]