Complete the square to solve the following quadratic equation: x2−22x+1=15 .(1 point) Responses x=11+14−−√, 11−14−−√ x equals 11 plus Start Root 14 End Root comma 11 minus Start Root 14 End Root x=−11+14−−√, −11−14−−√ x equals negative 11 plus Start Root 14 End Root comma negative 11 minus Start Root 14 End Root x=11+315−−√, 11−315−−√ x equals 11 plus 3 Start Root 15 End Root comma 11 minus 3 Start Root 15 End Root x=−11+315−−√, −11−315−−√

1 answer

To complete the square, we need to rearrange the equation to isolate the quadratic term and then take half of the coefficient of the linear term squared.

Starting with the equation x^2 - 22x + 1 = 15, subtracting 1 from both sides gives us x^2 - 22x = 14.

To complete the square, we take half of the coefficient of the linear term, which is -22, and square it to get (-22/2)^2 = 11^2 = 121.

To balance the equation, we add 121 to both sides, resulting in x^2 - 22x + 121 = 14 + 121, or (x-11)^2 = 135.

Now we take the square root of both sides to solve for x, giving us x-11 = ±√135.

Adding 11 to both sides yields x = 11 ± √135.

So, the correct response is x = 11 ± √135.
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