Complete the square for this conic section in standard form:

x^2+y^2-6x+4y-12=0

1 answer

x^2+y^2-6x+4y-12=0
x^2 - 6x + 9 + y^2 + 4y 4 = 12 + 9 + 4

(x-3)^2 + (y+2)^2 = 25