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Complete the square for this conic section in standard form:
x^2+y^2-6x+4y-12=0
1 answer
x^2+y^2-6x+4y-12=0
x^2 - 6x +
9
+ y^2 + 4y
4
= 12 +
9
+
4
(x-3)^2 + (y+2)^2 = 25
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