complete the square

2x^2-4x-1=0

1 answer

solve by completing the square ??

first divide by 2 and move the constant to the right ...

x^2 - 2x = 1
add 1 to both sides
x^2 - 2x + 1 = 1 + 1
(x-1)^2 = 2
x-1 = ± √2

x = 1 ± √2
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