This equation will have one solution when \( h = 1 \) because you get one solution when you have an equal number of \( x \)'s on either side of the equation and the constants balance out.
The left-hand side of the equation can be expressed as \( 14x + 70 \) while the right-hand side can be expressed as \( h(2x + 10) \). For there to be one solution, the coefficients of \( x \) must match when \( h = 1 \), giving us \( 14x = 2x + 10 \), which simplifies to a single \( x \) solution if the constants also balance out (70 and 10).