To solve the equation \( 8b + 4 + 3b = 9b + 16 \), we can follow a structured process to isolate \( b \). Here’s how it goes step by step:
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Combine like terms on the left side: \[ 8b + 3b + 4 = 9b + 16 \implies 11b + 4 = 9b + 16 \]
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Subtract \( 9b \) from both sides to get all \( b \) terms on one side: \[ 11b - 9b + 4 = 16 \implies 2b + 4 = 16 \]
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Subtract 4 from both sides: \[ 2b + 4 - 4 = 16 - 4 \implies 2b = 12 \]
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Divide both sides by 2 to solve for \( b \): \[ b = \frac{12}{2} \implies b = 6 \]
So the completed process and filled-in blanks result in:
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Initial setup: \[ 8b + 4 + 3b = 9b + 16 \]
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Combine like terms: \[ 11b + 4 = 9b + 16 \]
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Subtract \( 9b \) from both sides: \[ 2b + 4 = 16 \]
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Subtract 4 from both sides: \[ 2b = 12 \]
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Divide both sides by 2: \[ b = 6 \]
Thus, the final answer for \( b \) is \( b = 6 \).
Missing Terms and Descriptions:
- Combine like terms
- Subtract \( 9b \) from both sides
- Subtract 4 from both sides
- Divide both sides by 2
Simplification of fractions was not necessary in this case, as the fractions simplified cleanly to integers.