To determine the possible whole-number values for side \( a \) of the triangle given sides \( b = 6 \) and \( c = 7 \), we can use the triangle inequality theorem, which states that for any triangle with sides \( a, b, \) and \( c \):
- \( a + b > c \)
- \( a + c > b \)
- \( b + c > a \)
Let's apply these inequalities step by step:
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From \( a + b > c \): \[ a + 6 > 7 \implies a > 1 \]
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From \( a + c > b \): \[ a + 7 > 6 \implies a > -1 \quad \text{(This is always true since } a \text{ is positive)} \]
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From \( b + c > a \): \[ 6 + 7 > a \implies 13 > a \implies a < 13 \]
Combining these inequalities, we find that: \[ 1 < a < 13 \]
Since we are looking for whole-number values for \( a \), the range of possible values is: \[ a = 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 \]
Thus, the answer to complete the inequality is:
\[ a < 13 \]