My! You have a lot of different personas.
Tracy 10, Tracy, Glenn, etc. -- please use the same name for your posts.
Complete the hypothesis test with alternative hypothesis ƒÊd �‚ 0 based on the paired data that follows and d = O - Y. Use ƒ¿ = 0.01. Assume normality.
Oldest 188 174 192 196 65
Youngest 186 168 199 199 69
(a) Find t. (Give your answer correct to two decimal places.)
Correct: Your answer is correct.0.52 .
(ii) Find the p-value. (Give your answer correct to four decimal places.)
0.6036 I can not figure out how to find p value it always comes out wrong
Anyone know a simple way to determine the p-values, I keep missing them. If I see example I usually can figure it out but did not work this time. I have TI83 Calculator but can not figure out how to use it. So not sure if I can get it on it or not.
6 answers
There is different people using one computer, we meet at my house because it is center area and just use my computer instead of everyone dragging their computer around. Sorry,
From now on there will only be one name used from this site, we have agreed upon it being Tracy since it my home.
Dependent
Different
xbar = -1.2
s = 5.17
n= 5
t = -1.2/(5.17/sqrt(5))
t = -0.52
p-value = 0.6310
To get p-value
Stat oldest L1, youngest L2
difference between oldest and youngest L3 after quit and stat tests then T-test data
List: L3
Different
xbar = -1.2
s = 5.17
n= 5
t = -1.2/(5.17/sqrt(5))
t = -0.52
p-value = 0.6310
To get p-value
Stat oldest L1, youngest L2
difference between oldest and youngest L3 after quit and stat tests then T-test data
List: L3
what do you mean with stat oldest L1, etc. Have a question I have a TI-83 Plus calculator, is there a way of putting in the information to get the p value or do you still have to look at a chart.
When I read the instructions on it, it mentioned finding the z value to get to the p value, I am confused I am so sorry.
When I read the instructions on it, it mentioned finding the z value to get to the p value, I am confused I am so sorry.
When you use your ti-83
Yes
L1, L2
Yes
L1, L2