To complete your two-column proof showing that \(\frac{\tan(\theta)}{\sin(\theta)} = \sec(\theta)\), we'll present the steps in the left column and the corresponding trig identities or simplifications in the right column.
Two-Column Proof
| Column 1 | Column 2 | |----------------------------------------|------------------------------------------------------------| | 1. \(\frac{\tan(\theta)}{\sin(\theta)}\) | Given | | 2. \(\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}\) | Definition of tangent | | 3. Substitute: \(\frac{\frac{\sin(\theta)}{\cos(\theta)}}{\sin(\theta)}\) | Substitution from step 2 | | 4. \(\frac{\sin(\theta)}{\cos(\theta)} \div \sin(\theta)\) | Simplification | | 5. \(\frac{\sin(\theta)}{\sin(\theta) \cdot \cos(\theta)}\) | Rewrite as division of fractions | | 6. \( \frac{1}{\cos(\theta)} \) | Cancel \(\sin(\theta)\) (provided \(\sin(\theta) \neq 0\)) | | 7. \(\sec(\theta)\) | Definition of secant (i.e., \(\sec(\theta) = \frac{1}{\cos(\theta)}\)) |
Final Conclusion
Thus, we have shown that \(\frac{\tan(\theta)}{\sin(\theta)} = \sec(\theta)\).
Key Trig Identities Used
- Definition of tangent: \(\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}\)
- Definition of secant: \(\sec(\theta) = \frac{1}{\cos(\theta)}\)
- Simplifying fractions by canceling similar terms.
This completes the proof!