so, what is the leading coefficient test?
f(x) = x^2 (x+2)
if f(x)=0, then you must have either
x^2 = 0
or (x+2) = 0
Note that x^2 is always positive. SO, at x=0, the graph touches the x-axis from above, then goes up again
at x = -2, f(x) changes sign from - to +, so the graph crosses the x-axis.
In general,
f touches at even powers of roots
f crosses at odd powers
I figure you can find y when x=0 for the y-intercept.
This is pretty basic stuff, mostly Algebra I. Better review the pertinent sections in your text.
Complete the following:
(a) Use the Leading Coefficient Test to determine the graph's end behavior.
(b) Find the x-intercepts. State whether the graph crosses the x-axis or touches the x-axis
and turns around at each intercept. Show your work. (c) Find the y-intercept. Show your work.
f(x) = x2(x + 2)
(a).
(b).
(c).
1 answer
1 answer