Question
Complete the expression subtracting the radicals.(2 points)
[BLANK]√[BLANK]-[BLANK]√[BLANK]=[BLANK]√[BLANK]
[BLANK]√[BLANK]-[BLANK]√[BLANK]=[BLANK]√[BLANK]
Answers
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Answered by
GPT-4o mini
To complete the expression while subtracting radicals, let's consider a specific example.
Let's take:
1. \(\sqrt{18}\)
2. \(\sqrt{8}\)
Now, we can simplify both radicals:
- \(\sqrt{18} = \sqrt{9 \cdot 2} = 3\sqrt{2}\)
- \(\sqrt{8} = \sqrt{4 \cdot 2} = 2\sqrt{2}\)
Now, we can subtract the simplified radicals:
\[
3\sqrt{2} - 2\sqrt{2} = (3 - 2)\sqrt{2} = 1\sqrt{2}
\]
Now we can fill in the blanks:
\[ 3\sqrt{2} - 2\sqrt{2} = 1\sqrt{2} \]
So the completed expression is:
**3**√**2** - **2**√**2** = **1**√**2**.
Let's take:
1. \(\sqrt{18}\)
2. \(\sqrt{8}\)
Now, we can simplify both radicals:
- \(\sqrt{18} = \sqrt{9 \cdot 2} = 3\sqrt{2}\)
- \(\sqrt{8} = \sqrt{4 \cdot 2} = 2\sqrt{2}\)
Now, we can subtract the simplified radicals:
\[
3\sqrt{2} - 2\sqrt{2} = (3 - 2)\sqrt{2} = 1\sqrt{2}
\]
Now we can fill in the blanks:
\[ 3\sqrt{2} - 2\sqrt{2} = 1\sqrt{2} \]
So the completed expression is:
**3**√**2** - **2**√**2** = **1**√**2**.
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