Complete the equation of the line through (-10,3) and (-8,-8) use exact numbers

Answer 1

First, we need to find the slope of the line using the formula:

slope = (y2 - y1) / (x2 - x1)

Using the points (-10,3) and (-8,-8), we get:

slope = (-8 - 3) / (-8 - (-10))
= (-8 - 3) / (-8 + 10)
= (-11) / 2

Now, we can use the point-slope form of the equation of a line to find the equation of the line:

y - y1 = m(x - x1)

Using the point (-10,3) and the slope (-11/2), we get:

y - 3 = (-11/2)(x - (-10))
y - 3 = (-11/2)(x + 10)

Multiplying both sides of the equation by 2 to eliminate the fraction, we get:

2(y - 3) = -11(x + 10)
2y - 6 = -11x - 110
2y = -11x - 104

The equation of the line through (-10,3) and (-8,-8) is:
2y = -11x - 104