To find the equation of the line through (-10,3) and (-8,-8), we first need to find the slope of the line.
The slope (m) can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)
Substituting the coordinates (-10,3) and (-8,-8), we get:
m = (-8 - 3) / (-8 - (-10))
Simplifying, we get:
m = (-8 - 3) / (-8 + 10)
m = -11 / 2
Now that we have the slope, we can use the point-slope form of the equation of a line to find the equation:
y - y1 = m(x - x1)
Substituting (-10,3) as the point (x1,y1), and the slope we calculated (-11/2) as m, we get:
y - 3 = (-11/2)(x - (-10))
Simplifying, we get:
y - 3 = (-11/2)(x + 10)
Expanding, we get:
y - 3 = (-11/2)x - 55
Rearranging the equation to solve for y, we get:
y = (-11/2)x - 52
complete the equation of the line through (-10,3) (-8,-8).
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