Compete the following nuclear equation:
235 4
92 u----> 2 He
a
Pa-231
b
U-235
c
Th - 231
d
Ac - 231
4 answers
b. U-235
√240x^12y^3 over 5xy^9
√50 over 2-√3
To rationalize the denominator (i.e., get rid of the radical in the denominator), we'll multiply both the numerator and denominator by the conjugate of the denominator, which is 2+√3:
√50 over 2-√3 * 2+√3 over 2+√3
Simplifying the numerator and denominator, we get:
(√50 * (2+√3)) / (4-3)
The denominator simplifies to 1, and we can simplify the numerator by multiplying the term inside the square root by 2:
(√100 * √3 + √50) / 1
Now we can just simplify further:
(10√3 + √50)
√50 over 2-√3 * 2+√3 over 2+√3
Simplifying the numerator and denominator, we get:
(√50 * (2+√3)) / (4-3)
The denominator simplifies to 1, and we can simplify the numerator by multiplying the term inside the square root by 2:
(√100 * √3 + √50) / 1
Now we can just simplify further:
(10√3 + √50)