To analyze the scenario you provided, I need to clarify a few things regarding the connections and the circuit configuration.
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Circuit A (with the switch connected to a rubber): Typically, rubber is an insulator and would not allow electrical current to flow. If the switch in Circuit A is connected to rubber and it is closed (or "on"), the circuit is likely incomplete, meaning the light bulb in this circuit would not produce light.
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Circuit B (with the switch connected to a fork): If the switch in Circuit B is connected to a fork, it's important to note that many metal forks are conductors of electricity. If the switch is closed in this circuit, it would allow current to flow, meaning that the light bulb in this circuit would produce light.
Conclusion:
- In Circuit A (connected to rubber), the light bulb will not produce light.
- In Circuit B (connected to a fork), the light bulb will produce light.
Thus, when both switches are "on," the light bulb in Circuit B will illuminate, while the bulb in Circuit A will remain dark.