Here are the answers to the questions:
Question 1: To find the slopes of the functions \( f(x) \) and \( g(x) \):
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For \( f(x) \), the points \( (0, -1) \) and \( (3, 1) \) give the slope: \[ \text{slope} = \frac{1 - (-1)}{3 - 0} = \frac{2}{3} \]
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For \( g(x) \), the points given in the table are:
- \( (0, 3) \) and \( (2, 6) \) \[ \text{slope} = \frac{6 - 3}{2 - 0} = \frac{3}{2} \]
Since \( \frac{2}{3} < \frac{3}{2} \): Answer: The slope of \( f(x) \) is less than the slope of \( g(x) \).
Question 2: The input of 6.5 friends doesn't make sense as we cannot have a fractional number of friends attending: Answer: No. The input is not possible.
Question 3: The vertex of the given absolute value function \( f(x) \) appears to be at \( (-4, 0) \) based on the values given, since \( f(-4) = 0 \) and the function increases from there:
- Range: The minimum value is \( 0 \) and increases indefinitely. Answer: Vertex (−4, 0), Range: {y | 0 ≤ y < ∞}.
Question 4: In the interval \( 2 < x < 4 \), Hannah's distance shows she is moving away from home at \( y= 4 \) until she decreases in distance after 3 hours implying she is returning home: Answer: It is decreasing in the interval 2 < x < 4 hours.
Question 5: To find the slope between the points (1, 7) and (5, 15): Slope \( m = \frac{15 - 7}{5 - 1} = \frac{8}{4} = 2 \). Thus, the equation in slope-intercept form is: \[ y - 7 = 2(x - 1) \rightarrow y = 2x + 5 \] Answer: \( f(x) = 2x + 5 \).
Question 6: The slope of the line \( y = 4x + 6 \) is 4; therefore, the slope of the perpendicular line will be \( -\frac{1}{4} \). Using point-slope form with point (8, -4): \[ y + 4 = -\frac{1}{4}(x - 8) \rightarrow y = -\frac{1}{4}x + 2 \] Answer: \( y = -\frac{1}{4}x + 2 \).
Question 7: Revising \( y = f(x) - 9 \) results in the graph being shifted downwards: Answer: The graph of \( y = f(x) \) will shift down 9 units.
Question 8: Since the absolute value function \( f(x) = |x| \) has a minimum value of 0, translating it down 5 yields: Answer: \( -5 ≤ y < ∞ \).
Question 9: To find the intercepts:
- Set \( y = 0 \): \( 3x = -18 \rightarrow x = -6 \).
- Set \( x = 0 \): \( 9y = -18 \rightarrow y = -2 \). Thus, the line goes through \( (-6, 0) \) and \( (0, -2) \): Answer: line through the points -6, 0 and 0, -2.
Question 10: The domain of the function is represented by the x-coordinates: Answer: {−3, 0, 4, 11}.
Question 11: Substituting into \( h(x) = -4(-5) - 10 \): \[ h(-5) = 20 - 10 = 10 \] Answer: 10.
Question 12: Calculate \( g(-2) \) and \( g(4) \): \[ g(-2) = 10, \quad g(4) = -8 \] Thus, \( g(-2) > g(4) \): Answer: The value of \( g(-2) \) is larger than the value of \( g(4) \).
Question 13: The x-intercept where the amount of air is 0 indicates the time until all air is leaked: Answer: (8, 0); the time it takes all the air to leave the inflatable.
Question 14: Revising \( y = f(x-2) \) translates to the right: Answer: The graph of \( y = f(x) \) will shift right 2 units.
Question 15: Finding the slope with \( y = mx + b \): The slope from 90 to 60 reduces over 5 weeks: \[ m = \frac{60 - 90}{10 - 5} = -6 \] With the y-intercept \( b = mx + b\), at \( x = 5, y = 90 \): \[ 90 = -6(5) + b \rightarrow b = 120 \] The function becomes: Answer: \( f(x) = -6x + 120 \).
Feel free to ask if you need clarification on any specific answer!